{"id":639146,"date":"2026-03-20T04:54:50","date_gmt":"2026-03-20T11:54:50","guid":{"rendered":"https:\/\/www.swimmingworldmagazine.com\/news\/?p=639146"},"modified":"2026-03-20T07:40:50","modified_gmt":"2026-03-20T14:40:50","slug":"flash-cam-mcevoy-rockets-to-50-free-world-record-in-20-88","status":"publish","type":"post","link":"https:\/\/www.swimmingworldmagazine.com\/news\/flash-cam-mcevoy-rockets-to-50-free-world-record-in-20-88\/","title":{"rendered":"FLASH! Cam McEvoy Rockets To 50 Free World Record In 20.88"},"content":{"rendered":"

FLASH! Cam McEvoy Rockets To 50 Free World Record In 20.88<\/h4>\n
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Cam McEvoy<\/strong> redefined the 50 free world record as he rocketed to 20.88 to consign Cesar Cielo\u2019s<\/strong> 2009 standard to history at the China Open.<\/p>\n
Cielo\u2019s mark of 20.91 had stood since December 2009 as the supersuit era staggered towards its end. The Brazilian himself had surpassed Fred Bousquet\u2019s<\/strong> 20.94 WR mark from April 2009 with the pair the only two men to break 21secs.<\/p>\n
That was until McEvoy went 0.03 inside Cielo\u2019s mark with the Australian now holding the world record on top of the Olympic and world crowns with his wife Madeline and son Hartley present in Shenzhen to witness the 31-year-old make history.<\/p>\n
Caeleb Dressel<\/strong> was the fastest man in textile until today, twice posting 21.04 in 2019 and 2021, with the American third fastest in history, 0.02 ahead of McEvoy who posted 21.06 en-route to the world title at Fukuoka 2023.<\/p>\n
$\"\"$ <\/p>\n
Now McEvoy stands at the summit, 16 years and three months after Cielo set that world record and he posted to social media, saying:<\/p>\n
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“WORLD RECORD!! 20.88s<\/p>\n
\u201cThe chance is high that the truth lies in the fashionable direction. But, on the off-chance that it is in another direction \u2014 who will find it? Only someone who has sacrificed himself by teaching himself from a peculiar and unfashionable point of view; one that he may have to invent for himself\u201c – Richard Feynman<\/p>\n
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